F(2)=2x^2-5x+6

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Solution for F(2)=2x^2-5x+6 equation: 



(2)=2F^2-5F+6

We move all terms to the left:

(2)-(2F^2-5F+6)=0

We get rid of parentheses

-2F^2+5F-6+2=0

We add all the numbers together, and all the variables

-2F^2+5F-4=0

a = -2; b = 5; c = -4;
Δ = b2-4ac
Δ = 52-4·(-2)·(-4)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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